@qNUMBER TUTORIAL -- PART 1. This is a Tutorial on Number Word Problems. If you find a question confusing, use the `HELP' key.@dg08@pIf the Tutorial seems too easy, use the `Skip Problem' key. (Any key to continue.)@hThere are always two HELP's available. The second time you press the HELP key you get the correct answer.@hThe `Skip Problem' key will take you to the next problem, or to the next part of the Tutorial.@i(0)@jNumber Problems introduce algebra word problems.&d(0,Number Problems focus on translating from English into formulas.)@jTranslate the sentences in five stages.@r1. READ&d(1,1. Read the complete problem.)&d(0,Read everything slowly and carefully. Think: What are the facts? What is being asked?)@r2. IDENTIFY THE UNKNOWN&d(2,2. Identify the unknown.)&d(0,Use a letter, such as `x'\, to represent the unknown quantity.)@r3. SUBDIVIDE&d(3,3. Break the sentence into parts.)&d(0,Use key words to divide sentences in parts. Words such as `is' or `equals' translate as `='.)&d(0,The `=' sign shows the two sides of the equation. Use parentheses\n( ) to show the sides in the sentence.)@r4. BEGIN TRANSLATING&d(4,4. Work inside the ( ) first.)&d(0,Words like `times' and `product of' indicate multiplication.)@r5. FINISH TRANSLATING&d(5,5. Finish the translation.)&d(0,Words like `increased by' and `sum of' indicate addition.)@dg08@jHere are parts of sentences that might appear in number word problems. Use the letter `x' as the variable.&d(0,)@r1. READ&c(1,3 times the number "x", increased by 6.)&d(0,Read the sentence slowly and carefully. Make sure you understand everything.)@r2. IDENTIFY THE UNKNOWN&d(2,      3 times )@pReplace the phrase `the number "x" ' with `x'. Remember, use HELP if you need it.@hUse the letter `x' as a variable to represent the unknown.@hEnter the letter `x' and press the <Return> key.@i(2,d0,)&c(2,3 times x, increased by 6.)@r3. SUBDIVIDE&d(0,)&c(3,( 3 times x ) increased by 6.)&d(0,Notice the phrasing in the sentence. Commas are a clue to grouping.)@r4. BEGIN TRANSLATING&d(4,       3 )@pWork on the phrase inside parentheses first: `times' indicates multiplication.@hUse the multiplication sign, `*', to translate "times".@hEnter `* x' and press the <Return> key.@i(4,d0,)&c(4,(3 * x) increased by 6.)@r5. FINISH TRANSLATING&d(0,)&c(5,(3 * x))@pThe words `increased by' indicate addition.@hUse the addition sign, `+', to translate "increased by" .@hEnter `+6' and press the <Return> key.@i(5,j,3x+6)@s @dg08@r1. READ&c(1,6 times the number "x", decreased by 10.)&d(0,Read the sentence slowly. Make sure you understand everything.)&d(2,     6 times )@r2. IDENTIFY THE UNKNOWN@pThe phrase `the number "x" ' is replaced with `x'.@hUse the letter 'x' as a variable to represent the unknown.@hEnter the letter 'x' and press the <Return> key.@i(2,d0,)&c(2,6 times x, decreased by 10.)@r3. SUBDIVIDE&d(0,)&c(3,(6 times x) decreased by 10.)&d(0,Notice the phrasing in the sentence. Commas are a clue to the grouping.)@r4. BEGIN TRANSLATING&d(4,        6 )@pWork on the phrase inside parentheses first: `times' indicates multiplication.@hUse the multiplication sign, `*', to translate "times".@hEnter `* x' and press the <Return> key.@i(4,d0,)&c(4,(6 * x) decreased by 10.)@r5. FINISH TRANSLATING&d(0,)&c(5,(6 * x) )@pThe words `decreased by' indicate subtraction.@hUse the subtraction sign, `-', to translate "decreased by".@hEnter  `- 10' and press the <Return> key.@i(5,j,6x-10)@dg08@r1. READ&c(1,The product of 7 and a number is 56.)&d(0,)&d(2,    The product of 7 and )@r2. IDENTIFY THE UNKNOWN@pReplace "a number" with the variable `x'. Remember, ask for HELP if you need it.@hThe English phrase "a number" is replaced by a variable: `x'.@hEnter `x' and press the <Return> key.@i(2,d0,)&c(2,The product of 7 and x is 56.)@r3. SUBDIVIDE&c(3,( The product of 7 and x ) = 56.)&d(0,The word "is" is replaced by `='. This splits the sentence into the two sides of the equation.)&d(0,The equal sign " = " divides mathematical equations in two parts.)@r5. FINISH TRANSLATING&d(4,      7 ).@pThe phrase "the product of" indicates multiplication.@hComplete the translation.@hEnter `* x = 56' and press the <Return> key.@i(4,j,7x=56) @qNUMBER TUTORIAL -- PART 2. Here is a complete problem to show how to use a grid.@dg06&d(2,EQUATION)&d(5,CHECK)@r&d(0,)@jIf 10 is added to 2 times some number, the result is 28. What is the number?@rREAD@pRead the problem slowly and carefully. What is being asked? Press any key to continue.@hWhat is being asked? You are being asked to find the unknown number.@hThe problem is to find &hsome number&h.&qWhat is the number?&q@i(0)@rPLAN@pIdentify the unknown: Choose a variable to represent the unknown number.@hUse any letter as a variable to represent the unknown number.@hChoose any letter, such as `n' to represent the unknown number.@i(1,i,&v)&d(1,The unknown number is:  &v)&d(0,Use the five steps to translate the first phrase into a mathematical expression.&qIf 10 is added to 2 times some number&q)@dg08&d(1,If 10 is added to 2 times some number)@r1. READ&d(0,)@r2. IDENTIFY THE UNKNOWN&d(2,    If 10 is added to 2 times )@pReplace "some number" with `&v'.@hUse the letter `&v' to represent the unknown.@hEnter the letter `&v' and press the <Return> key.@i(2,d0,)&c(2,If 10 is added to 2 times &v)@r3. SUBDIVIDE&d(0,)&c(3,If 10 is added to (2 times &v))&d(0,)@r4. BEGIN TRANSLATING&d(4,     If 10 is added to  2 )@pWork on the part inside parentheses first.@h"times" indicates multiplication.@hEnter `* &v'  and press the <Return> key.@i(4,d0,)&c(4,If 10 is added to (2 * &v))@r5. FINISH TRANSLATING@pEnter the entire expression.@hThe phrase "is added to" indicates addition.@hEnter `10 + (2*&v)' and press the <Return> key.@i(5,i,10+2&v)@pTranslate the rest of the problem.&qThe result is 28&q@h"&hThe result is 28&h" is the phrase to be translated.@hTo translate &hthe result is 28&h, enter `= 28'.@i(5,j,2&v+10=28)@s@dg06&d(1,The unknown number is:  &v)&d(2,EQUATION)&d(3,10 + 2&v = 28)&d(5,CHECK)@rCOMPUTE&d(4,10+2&v = 28)@pUse the Calculator to solve the equation "10+2&v = 28".@hThe Calculator solves equations for you and displays the steps in the solution.@hYou may also solve this yourself. Isolate "&v" on one side of the equation. Enter `&v = 9'.@i(4,i,&v=9)@rCHECK&d(6,2*&v+10=28)@pCheck your work by substituting for "&v" in the equation.@h&v = 9. So substitute 9 for "&v".@hMove the cursor over `&v', type `9' and press the <Return> key.@i(6,i,2*9+10=28)@pUse the calculator to check that the equation balances.@hThe Calculator solves equations for you and displays the steps in the solution.@hSince (2*9)+10=28, and the right side already equals 28, the result of the checking is `28=28'.@i(6,i,28=28)@s@r&d(0,You are now ready to practice Number Word Problems. Select "Number Word Problems" "Level 2".)|